python 3.2 调用随机函数生成10个数,冒泡排序

下面这个脚本只是学习并练习用的，请不要“鸡蛋里挑骨头”，呵呵

import random

print("randrange:append ten numbers from 0 to 100 to list1 array:")
list1 = []
for i in range(11):
    a = random.randrange(0,100)
    list1.append(a)

for i in range(11):
    print("list1[%d] = %3d" % (i,list1[i]))

print("randint:append ten numbers from 101 to 200 to list2 array:")
list2 = []
for i in range(11):
    b = random.randint(101,200)
    list2.append(b)

for i in range(11):
    print("list2[%d] = %4d" % (i,list2[i]))

print("uniform.:append ten numbers from 201 to 300 to list array:")
list3 = []
for i in range(11):
    c = random.uniform(201,300)
    list3.append(c)

for i in range(11):
    print("list3[%d] = %10.4f" % (i,list3[i]))

print("random:append ten numbers from () to list array:")
list4 = []
for i in range(11):
    d = random.random()
    list4.append(d)

for i in range(11):
    print("list4[%d] = %20.18f" % (i,list4[i]))

print("choice:append ten numbers from list1 to list array:")
list5 = []
for i in range(11):
    c = random.choice(list1)
    list5.append(c)

for i in range(11):
    print("list5[%d] = %3d" % (i,list5[i]))

for i in range(11):
    for j in range(11):
        if list1[i] < list1[j]:
            list1[i],list1[j] = list1[j],list1[i]

        if list2[i] < list2[j]:
            list2[i],list2[j] = list2[j],list2[i]

        if list3[i] < list3[j]:
            list3[i],list3[j] = list3[j],list3[i]

        if list4[i] < list4[j]:
            list4[i],list4[j] = list4[j],list4[i]

        if list5[i] < list5[j]:
            list5[i],list5[j] = list5[j],list5[i]

for i in range(11):
    print("list1[%d] = %3d" % (i,list1[i]))

for i in range(11):
    print("list2[%d] = %4d" % (i,list2[i]))

for i in range(11):
    print("list3[%d] = %10.4f" % (i,list3[i]))

for i in range(11):
    print("list4[%d] = %20.18f" % (i,list4[i]))

for i in range(11):
    print("list5[%d] = %3d" % (i,list5[i]))

print("done5")