显示行号：

Select no=Identity(int,1,1),* Into #temptable From titles --Order By SortField
Select * From #temptable  --Where no>=6 And no < 10
Drop Table #temptable

查重：

use pubs

select au_lname from authors group by au_lname having count(1)>1

（转载）某外企SQL Server面试题(数据库面试题)
SQL Server面试题, 数据库面试题
Question 1：Can you use a batch SQL or store procedure to calculating the Number of Days

in a Month
Answer 1：找出当月的天数

 程序代码
select datepart(dd,dateadd(dd,-1,dateadd(mm,1,cast(cast(year(getdate()) as varchar)

+'-'+cast(month(getdate()) as varchar)+'-01' as datetime))))

Question2：Can you use a SQL statement to calculating it!
How can I print "10 to 20" for books that sell for between $10 and $20，"unknown" for

books whose price is null, and "other" for all other prices?
Answer 2：
select bookid,bookname,price=case when price is null then 'unknown'
when price between 10 and 20 then '10 to 20' else price end
from books

Question3：Can you use a SQL statement to finding duplicate values!
How can I find authors with the same last name?
You can use the table authors in datatabase pubs. I want to get the result as below:
Output:

 程序代码
au_lname number_dups
---------------------------------------- -----------
Ringer 2

(1 row(s) affected)
Answer 3
select au_lname,number_dups=count(1) from authors group by au_lname

Question4：Can you create a cross-tab report in my SQL Server!
How can I get the report about sale quality for each store and each quarter and the

total sale quality for each quarter at year 1993?
You can use the table sales and stores in datatabase pubs.
Table Sales record all sale detail item for each store. Column store_id is the id of

each store, ord_date is the order date of each sale item, and column qty is the sale

qulity. Table stores record all store information.
I want to get the result look like as below:
Output:

 程序代码
stor_name Total Qtr1 Qtr2 Qtr3 Qtr4
---------------------------------------- ----------- ----------- ----------- -----------

-----------
Barnum's 50 0 50 0 0
Bookbeat 55 25 30 0 0
Doc-U-Mat: Quality Laundry and Books 85 0 85 0 0
Fricative Bookshop 60 35 0 0 25
Total 250 60 165 0 25

Answer 4：用动态SQL实现

Question5: The Fastest Way to Recompile All Stored Procedures
I have a problem with a database running in SQL Server 6.5 (Service Pack 4). We moved

the database (object transfer) from one machine to another last night, and an error

(specific to a stored procedure) is cropping up. However, I can't tell which procedure

is causing it. Permissions are granted in all of our stored procedures; is there a way

from the isql utility to force all stored procedures to recompile?

Tips: sp_recompile can recomplie a store procedure each time
Answer 5：在执行存储过程时,使用 with recompile 选项强制编译新的计划；使用sp_recompile系

统存储过程强制在下次运行时进行重新编译

Question6: How can I add row numbers to my result set?
In database pubs, have a table titles , now I want the result shown as below,each row

have a row number, how can you do that?
Result:

 程序代码
line-no title_id
----------- --------
1 BU1032
2 BU1111
3 BU2075
4 BU7832
5 MC2222
6 MC3021
7 MC3026
8 PC1035
9 PC8888
10 PC9999
11 PS1372
12 PS2091
13 PS2106
14 PS3333
15 PS7777
16 TC3218
17 TC4203
18 TC7777

Answer 6：
--SQL 2005的写法
select row_number() as line_no ,title_id from titles
--SQL 2000的写法
select line_no identity(int,1,1),title_id into #t from titles
select * from #t
drop table #t

Question 7: Can you tell me what the difference of two SQL statements at performance of

execution?
Statement 1:

 程序代码
if NOT EXISTS ( select * from publishers where state = 'NY')
begin
Select 'Sales force needs to penetrate New York market'
end
else
begin
Select 'We have publishers in New York'
end
Statement 2:
if EXISTS ( select * from publishers where state = 'NY')
begin
Select 'We have publishers in New York'
end
else
begin
Select 'Sales force needs to penetrate New York market'
end

Answer 7：不同点:执行时的事务数,处理时间,从客户端到服务器端传送的数据量大小

Question8: How can I list all California authors regardless of whether they have written

a book?
In database pubs, have a table authors and titleauthor , table authors has a column

state, and titleauhtor have books each author written.
CA behalf of california in table authors.
Answer 8：
select * from authors where state='CA'

Question9: How can I get a list of the stores that have bought both 'bussiness' and

'mod_cook' type books?
In database pubs, use three table stores,sales and titles to implement this requestment.
Now I want to get the result as below:
stor_id stor_name
------- ----------------------------------------
...
7896 Fricative Bookshop
...
...
...
Answer 9：

 程序代码
select distinct a.stor_id, a.stor_name from stores a,sales b,titles c
where a.stor_id=b.stor_id and b.title_id=c.title_id and c.type='business' and
exists(select 1 from sales k,titles g where stor_id=b.stor_id
and k.title_id=g.title_id and g.type='mod_cook')

 

Question10: How can I list non-contignous data?
In database pubs, I create a table test using statement as below, and I insert several

row as below

 程序代码
create table test
( id int primary key )
go

insert into test values (1 )
insert into test values (2 )
insert into test values (3 )
insert into test values (4 )
insert into test values (5 )
insert into test values (6 )
insert into test values (8 )
insert into test values (9 )
insert into test values (11)
insert into test values (12)
insert into test values (13)
insert into test values (14)
insert into test values (18)
insert into test values (19)
go

Now I want to list the result of the non-contignous row as below,how can I do it?

 程序代码
Missing after Missing before
------------- --------------
6 8
9 11
...

Answer 10：
select id from test t where not exists(select 1 from test where id=t.id+1)
or not exists(select 1 from test where id=t.id-1)

Question11: How can I list all book with prices greather than the average price of books

of the same type?
In database pubs, have a table named titles , its column named price mean the price of

the book, and another named type mean the type of books.
Now I want to get the result as below:

 程序代码
type     title                                 price
business The Busy Executive's Database Guide   19.9900

Answer 11：

 程序代码
select a.type,a.title,a.price from titles a,
(select type,price=avg(price) from titles group by type)b
where a.type=b.type and a.price>b.price

试题点评：通览整个试题，我们不难发现，这份试题是针对SQL Server数据库人员的。而从难度分析

上来看，这份试题也属于同类试题中比较难的了。之所以说它难，首先是限定时间的全英文试题；其

次，尽管这份试题主要是考核开发能力，但却涉及到了算法的选择和性能的调优；最后，这份试题还

夹进了SQL Server数据库的升级问题。因此，综上所述，我们估计这是一家从事程序外包工作的外企

招聘后台开发或与后台开发相关的SQL Server高级程序员的试题。