因此要想完成长按并拖动的操作，只要在ACTION_DOWN之后，停留一段时间即可模拟长按操作。
| /** * 实现将一个视图拖动到另一个视图所在的位置 * @param viewFrom 起始View * @param viewTo 终点View * @throws Exception */ public void clickLongAndDrag(View viewFrom,View viewTo) throws Exception { //获得视图View中手机屏幕上的绝对x、y坐标 final int[] location = new int[2]; final int[] location2 = new int[2]; viewFrom.getLocationOnScreen(location); viewTo.getLocationOnScreen(location2); float xStart=location[0]; float yStart=location[1]; float xStop=location2[0]; float yStop=location2[1]; Log.i(TAG, "xStart:"+String.valueOf(xStart)); Log.i(TAG, "yStart:"+String.valueOf(yStart)); Log.i(TAG, "xStop:"+String.valueOf(xStop)); Log.i(TAG, "yStop:"+String.valueOf(yStop)); long downTime = SystemClock.uptimeMillis(); long eventTime = SystemClock.uptimeMillis(); try{ MotionEvent event = MotionEvent.obtain(downTime, eventTime, MotionEvent.ACTION_DOWN, xStart+10f, yStart+10f, 0); inst.sendPointerSync(event); //event = MotionEvent.obtain(downTime, eventTime, MotionEvent.ACTION_MOVE, xStart+10f+1.0f, yStart+10f+1.0f, 0); //inst.sendPointerSync(event); //Thread.sleep(1000); //延迟一秒，模拟长按操作 eventTime = SystemClock.uptimeMillis() + 1000; //xStop加了10点坐标，获得的View坐标需根据应用实际情况稍做一点调整 event = MotionEvent.obtain(downTime, eventTime, MotionEvent.ACTION_MOVE, xStop+10f, yStop+50f, 0); inst.sendPointerSync(event); eventTime = SystemClock.uptimeMillis() + 1000; //又再小小移动了一次，不这么做的话可以无法激活被测应用状态，导致View移动后又回复到原来位置 event = MotionEvent.obtain(downTime, eventTime, MotionEvent.ACTION_MOVE, xStop+10f, yStop+10f, 0); inst.sendPointerSync(event); eventTime = SystemClock.uptimeMillis() + 1000; event = MotionEvent.obtain(downTime, eventTime, MotionEvent.ACTION_UP, xStop+10f, yStop+10f, 0); inst.sendPointerSync(event); }catch (Exception ignored) { // Handle exceptions if necessary } } |
