用Python绘制表白玫瑰花

发表于:2022-10-25 09:48

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 作者:脑壳二    来源:CSDN

  一、玫瑰花绘制—深红色
  import numpy as np
  import matplotlib.pyplot as plt
  from mpl_toolkits.mplot3d import Axes3D
  fig = plt.figure()
  ax = fig.gca(projection='3d')
  [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 30 * np.pi - 4*np.pi)
  p = (np.pi / 2) * np.exp(-t / (8 * np.pi))
  change = np.sin(20*t)/50
  u = 1 - (1 - np.mod(3.3 * t, 2 * np.pi) / np.pi) ** 4 / 2 + change
  y = 2 * (x ** 2 - x) ** 2 * np.sin(p)
  r = u * (x * np.sin(p) + y * np.cos(p)) * 1.5
  h = u * (x * np.cos(p) - y * np.sin(p))
  c= plt.get_cmap('magma')
  surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,
                         cmap= c, linewidth=0, antialiased=True)
  plt.show()
  二、玫瑰花绘制—五颜六色
  import numpy as np
  import matplotlib.pyplot as plt
  from matplotlib import cm
  from mpl_toolkits.mplot3d import Axes3D
  fig = plt.figure()
  ax = fig.gca(projection='3d')
  [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 17 * np.pi - 2 * np.pi)
  p = (np.pi / 2) * np.exp(-t / (8 * np.pi))
  u = 1 - (1 - np.mod(3.6 * t, 2 * np.pi) / np.pi) ** 4 / 2
  y = 2 * (x ** 2 - x) ** 2 * np.sin(p)
  r = u * (x * np.sin(p) + y * np.cos(p))
  h = u * (x * np.cos(p) - y * np.sin(p))
  c= cm.gist_rainbow_r
  surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,
                         cmap= c, linewidth=0, antialiased=True)
  plt.show()
  三、玫瑰花绘制—粉红色
  import numpy as np
  import matplotlib.pyplot as plt
  from matplotlib import cm
  from mpl_toolkits.mplot3d import Axes3D
  fig = plt.figure()
  ax = fig.gca(projection='3d')
  [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 17 * np.pi - 2 * np.pi)
  p = (np.pi / 2) * np.exp(-t / (8 * np.pi))
  u = 1 - (1 - np.mod(3.6 * t, 2 * np.pi) / np.pi) ** 4 / 2
  y = 2 * (x ** 2 - x) ** 2 * np.sin(p)
  r = u * (x * np.sin(p) + y * np.cos(p))
  h = u * (x * np.cos(p) - y * np.sin(p))
  c= cm.get_cmap('spring_r')
  surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,
                         cmap= c, linewidth=0, antialiased=True)
  plt.show()
  四、玫瑰花绘制—红色
  # 省略了头文件,可以在之前的博客里看到
  import numpy as np
  import matplotlib.pyplot as plt
  from mpl_toolkits.mplot3d import Axes3D
  fig = plt.figure()
  ax = fig.gca(projection='3d')
  # 将相位向后移动了6*pi
  [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 20 * np.pi + 4*np.pi)
  p = (np.pi / 2) * np.exp(-t / (8 * np.pi))
  # 添加边缘扰动
  change = np.sin(15*t)/150
  # 将t的参数减少,使花瓣的角度变大
  u = 1 - (1 - np.mod(3.3 * t, 2 * np.pi) / np.pi) ** 4 / 2 + change
  y = 2 * (x ** 2 - x) ** 2 * np.sin(p)
  r = u * (x * np.sin(p) + y * np.cos(p))
  h = u * (x * np.cos(p) - y * np.sin(p))
  c= plt.get_cmap('Reds')
  surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,
                         cmap= c, linewidth=0, antialiased=True)
  plt.show()
  五、桃花绘制
  import numpy as np
  import matplotlib.pyplot as plt
  from mpl_toolkits.mplot3d import Axes3D
  fig = plt.figure()
  ax = fig.gca(projection='3d')
  [x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 6 * np.pi - 4*np.pi)
  p = (np.pi / 2) * np.exp(-t / (8 * np.pi))
  change = np.sin(10*t)/20
  u = 1 - (1 - np.mod(5.2 * t, 2 * np.pi) / np.pi) ** 4 / 2 + change
  y = 2 * (x ** 2 - x) ** 2 * np.sin(p)
  r = u * (x * np.sin(p) + y * np.cos(p)) * 1.5
  h = u * (x * np.cos(p) - y * np.sin(p))
  c= plt.get_cmap('spring_r')
  surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,
                         cmap= c, linewidth=0, antialiased=True)
  plt.show()
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