用python判断字符串是否是回文结构

上一篇 / 下一篇 2014-06-05 17:30:42 / 个人分类：Python

第一种：通过字符串前后对比

Str = input("Please input one string:")

newStr = str(Str)

flag = True

for i in range(int(len(newStr)/2)):

if newStr[i]!=newStr[len(newStr)-i-1]:

flag = False

break

if flag:

print("%s is huiwen number!" %Str)

else:

print("%s is not huiwen number!" %Str)

第二种：更为简单，把字符串转为list，然后reverse，把两个字符串对比

import string

import copy

#get the str from command line

Str = input("Please input one str that you want to check:")

punctuation = string.punctuation #string.punctuation里面包含了32个英文标点符号

identify = ' '*32

table = Str.maketrans(punctuation, identify)#maketrans接受两个等长的参数，形成一个对应表

newStr = Str.translate(table).replace(' ', '')#先用对应表和translate函数将字符串里面的标点符号用空格代替，然后去掉空格

inputStr = list(newStr)

temp = copy.deepcopy(inputStr)

inputStr.reverse()

if (temp == inputStr):

print("Yes, it is!")

else:

print("sorry, this str is not!")

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