如果不特别说明，sed例子中使用下述文本文本quote.txt的内容：
The honeysuckle band played all night long for only $90.
It was an evening of splendid music and company.
Too bad the disco floor fell through at 23:10.
The local nurse Miss P.Neave was in attendance.
四、实例(续)
1.使用&实现附加或修改字符串
[root@RHEL5 shell]# sed -n 's/nurse/"Hello" &/p' quote.txt
The local "Hello" nurse Miss P.Neave was in attendance.
[root@RHEL5 shell]# sed -n 's/played/"from Hockering" &/p' quote.txt
The honeysuckle band "from Hockering" played all night long for only $90.
2.将sed输出结果写入文件
[root@RHEL5 shell]# sed '1,2 w sed.out' quote.txt
The honeysuckle band played all night long for only $90.
It was an evening of splendid music and company.
Too bad the disco floor fell through at 23:10.
The local nurse Miss P.Neave was in attendance.
[root@RHEL5 shell]# cat sed.out
The honeysuckle band played all night long for only $90.
It was an evening of splendid music and company.
可以看出，显示在屏幕上的是所有行，而写入文件的只有第1 2行。
3.从文件中读取
创建一个文本
test.txt，内容为：Boom boom went the music
[root@RHEL5 shell]# sed '/company/ r test.txt' quote.txt
The honeysuckle band played all night long for only $90.
It was an evening of splendid music and company.
Boom boom went the music
Too bad the disco floor fell through at 23:10.
The local nurse Miss P.Neave was in attendance.
所读的文件名需要用单引号括起来
4.匹配后退出
[root@RHEL5 shell]# sed '/.a.*/q' quote.txt
The honeysuckle band played all night long for only $90.
首次匹配后就退出
5.显示文件中的控制符
sed -n '1,$l' anony.txt
第一个参数是数字1，$后是小写的L。
五、使用系统sed
1.处理控制字符
现有一个dos.txt的文件，内容如下：
12332##DISO##45.12^M
00332##LPSO##23.11^M
01299##USPD##34.46^M
可采取以下动作：
(1) 用一个空格替换所有的##符号
[root@RHEL5 shell]# sed 's/##*/ /g' dos.txt
12332 DISO 45.12^M
00332 LPSO 23.11^M
01299 USPD 34.46^M
(2) 删除起始域中最前面的0(00)
[root@RHEL5 shell]# sed 's/^0*//g' dos.txt
12332##DISO##45.12^M
332##LPSO##23.11^M
1299##USPD##34.46^M
(3) 删除行尾控制字符(^M)
[root@RHEL5 shell]# sed 's/\^M//g' dos.txt
12332##DISO##45.12
00332##LPSO##23.11
01299##USPD##34.46
写成一条语句：
[root@RHEL5 shell]# cat dos.txt |sed 's/##*/ /g' |sed 's/0*//g' |sed 's/\^M//g'
12332 DISO 45.12
332 LPSO 23.11
1299 USPD 34.46
2.处理报文输出
该实例以sql.txt内容为数据源：
[root@RHEL5 shell]# cat sql.txt
Database Size(MB) Date Created
--------------------------------------------
GOSOUTH 2244 12/11/97
TRISUD 5632 8/9/99
(2 rows affected)
---end---
对上述内容作一些处理：
(1) 使用s /-*//g删除横线- - - - - -
[root@RHEL5 shell]# sed 's/-*//g' sql.txt
Database Size(MB) Date Created
GOSOUTH 2244 12/11/97
TRISUD 5632 8/9/99
(2 rows affected)
(2) 使用/^$/d删除空行
[root@RHEL5 shell]# sed '/^$/d' sql.txt
Database Size(MB) Date Created
--------------------------------------------
GOSOUTH 2244 12/11/97
TRISUD 5632 8/9/99
(2 rows affected)
(3) 使用$d删除最后一行
[root@RHEL5 shell]# sed '$d' sql.txt
Database Size(MB) Date Created
--------------------------------------------
GOSOUTH 2244 12/11/97
TRISUD 5632 8/9/99
[root@RHEL5 shell]#
(4) 使用1d删除第一行
[root@RHEL5 shell]# sed '1d' sql.txt
--------------------------------------------
GOSOUTH 2244 12/11/97
TRISUD 5632 8/9/99
(2 rows affected)
(5) 使用awk {print $1}打印第一列
[root@RHEL5 shell]# awk '{print $1}' sql.txt
Database
--------------------------------------------
GOSOUTH
TRISUD
(2
[root@RHEL5 shell]# cat sql.txt | sed 's/-*//g' | sed '/^$/d' | sed '$d' | sed '1d' | awk '{print $1}'
GOSOUTH
TRISUD
或
[root@RHEL5 shell]# cat sql.txt | sed 's/-*//g' | sed '/^$/d' | sed '$d' | sed '1d' | cut -f 1
GOSOUTH
TRISUD
3.附加文本
现有文件pass.txt，内容如下：
AC456
AC1
AC492169
AC9967
AC88345
[root@RHEL5 shell]# sed 's/[0-9][0-9][0-9]*/& PASS/g' pass.txt
AC456 PASS
AC1
AC492169 PASS
AC9967 PASS
AC88345 PASS
4.快速实用命令
‘s/\.$// g’ 删除以句点结尾行
‘-e/abcd/d’ 删除包含abcd的行
‘s/[][][]*/[]/g’ 删除一个以上空格，用一个空格代替
‘s/^[][]*//g’ 删除行首空格
‘s/\.[][]*/[]/g’ 删除句点后跟两个或更多空格，代之以一个空格
‘/^$/d’ 删除空行
‘s/^.//g’ 删除第一个字符
‘s/COL\(...\)//g’ 删除紧跟COL的后三个字母
‘s/^\///g’ 从路径中删除第一个\
‘s/[]/[ ]//g’ 删除所有空格并用tab键替代
‘S/^[ ]//g’ 删除行首所有tab键
‘s/[ ]*//g’ 删除所有tab键
