下面为部分实现代码
public String GetCheckString(Bitmap bitmap) { UnCodebase ud = new UnCodebase(bitmap); ud.GrayByPixels(); ud.ClearPicBorder(2); ud.CutMap(14, 15, 0, 0); bitmap = ud.bmpobj; // bitmap = ud.ClearNoise(128, 1); String chkcode = ""; Bitmap[] arrmap = ud.SplitImg(bitmap, 4, 1); foreach (Bitmap item in arrmap) { String str = ud.GetCodebybitmap(item, 128); Boolean isEques = false; foreach (String strss in code) { String[] a = strss.Split(':'); if (str == a[1]) { chkcode += a[0]; isEques = true; break; } } if (!isEques) { String strCurrent = ""; double max = 0.0; foreach (String strss in code) { int len1, len2, min, count = 0; String[] a = strss.Split(':'); len1 = a[1].Length; len2 = str.Length; min = len1; if (min > len2) { min = len2; } for (int i = 0; i < min; i++) { if (str[i] == a[1][i]) { count++; } } double currrent = (count * 100.0 / min); if (max < currrent) { max = currrent; strCurrent = a[0].Trim(); } } chkcode += strCurrent.Trim(); } } return chkcode; } |
通过这些处理后,识别成功率在90+%以上,
下面附上测试地址,代码 100%C#实现,方便asp.net调用,如果是C/C++实现 asp.net 调非托管的有些麻烦,非得放到System32 或是一个绝对路径下麻烦
测试地址
http://www.fox163.com/UniconTest.aspx
