方法一:
WITH CTE AS ( SELECT A.Id,A.[Uid],UserName FROM ( SELECT A.[id], REPLACE(Split.a.value('.', 'NVARCHAR(max)'),'''','') AS [Uid] FROM ( SELECT [id], CAST ('<M>' + REPLACE(Uid, ',', '</M><M>') + '</M>' AS XML) AS [Uid] FROM A ) AS A CROSS APPLY [Uid].nodes ('/M') AS Split(a) ) A INNER JOIN dbo.B B ON A.[Uid]=B.[Uid] ) SELECT DISTINCT classList=stuff((select ',' +UserName from CTE B WHERE A.Id=B.Id for xml path('')),1,1,'') FROM CTE A |
方法二:
SELECT t.id,classList=STUFF(( SELECT ','+tt1.UserName FROM A tt left join B tt1 ON ''+tt.Uid+',' like '%'+tt1.Uid+',%' WHERE tt.id=t.id FOR XML PATH('')),1,1,'') FROM A t ORDER BY t.id |
方法三:
select id, (select UserName from B where Uid=t02.item) c into #ttt from dbo.A as t01 cross apply dbo.split(t01.Uid,',') as t02
select id,stuff((select ','+c from dbo.#ttt as tb01 where tb01.id=tb02.id for xml path('')),1,1,'') as classList
from dbo.#ttt as tb02 group by id
drop table #ttt
方法三需要添加内置方法:
create function split( @string varchar(255), @separator varchar(255) )returns @array table(item varchar(255)) as begin declare @begin int,@end int,@item varchar(255) set @begin = 1 set @end=charindex(@separator,@string,@begin) while(@end<>0) begin set @item = substring(@string,@begin,@end-@begin) insert into @array(item) values(@item) set @begin = @end+1 set @end=charindex(@separator,@string,@begin) end set @item = substring(@string,@begin,len(@string)+1-@begin) if (len(@item)>0) insert into @array(item) values(substring(@string,@begin,len(@string)+1-@begin)) return end |
下面们直接看结果吧:
表A:
表B:
最终结果:
跟根据讨论给出的方法,我个人给出这样的三种,如果有不对之处,请多多指教。
在这里我就不多文字咯,因为博客里面写再多文字别人看的时候都是看看最终是不是别人要的效果,是就学习不是直接拉到,欢迎各位朋友多多指教。